Lesson 7 · 30 min

Voltammetry: diffusion written in current

A glucose meter reads a current. After a potential step the current decays as 1/√t (Cottrell); in a cyclic voltammogram the peak current grows as √v and reversible peaks sit about 59/n mV apart — all computed from the diffusion equation.

In this lesson

  • Sketch a three-electrode cell and explain the roles of the working, reference and counter electrodes and the potentiostat
  • Use the diffusion equation to explain the Cottrell current and the growing diffusion layer after a potential step
  • Read the cyclic voltammogram of a reversible couple: peak potentials, a separation of about 59/n mV, peak current proportional to √v
  • Calculate peak currents with the Randles–Ševčík equation and judge whether electron transfer is reversible

People with diabetes prick their fingers several times a day. On the test strip an enzyme oxidises the glucose in the blood and hands the electrons to a “mediator” (often potassium ferricyanide); the meter applies a potential that reoxidises the reduced mediator and reads the current over a few seconds — a current proportional to the glucose concentration. Potentiometry measures a voltage while no current flows; voltammetry does the opposite: it controls the potential and measures the current. That current records how fast the reactant diffuses to the electrode, and how fast electrons cross.

Predict first

In a cyclic voltammogram of a reversible couple, the scan rate goes from 0.1 V/s to 0.4 V/s (four times faster). What happens to the peak current?

Pick an answer and lock it in before you look. A wrong guess teaches more than no guess.

The three-electrode cell and mass transport

A voltammetric cell has three electrodes. The reaction happens at a small working electrode (a glassy-carbon, platinum or gold disc); the reference electrode only measures and controls the working electrode’s potential and carries almost no current; the current returns through the counter electrode (a platinum wire). A potentiostat keeps adjusting the voltage on the counter electrode so that the working electrode sits at the set potential against the reference.

At the surface the ratio of oxidised form O to reduced form R obeys the Nernst equation — change the potential and the surface concentrations change at once. But reactant from the bulk has to reach the surface, by diffusion (driven by concentration gradients), migration (ions pushed by the field) or convection (stirring or thermal currents). A supporting electrolyte such as 0.1–1 M KCl carries the current so that migration of the analyte is negligible; with the solution still, only diffusion remains.

Step the potential suddenly to a value that oxidises every R at the surface: the surface concentration drops to zero and a depleted layer starts growing into the solution, about πDt\sqrt{\pi Dt} thick — some 47 µm after 1 s and 150 µm after 10 s. The current is proportional to the concentration gradient at the surface, which flattens as the layer thickens, so the current decays as 1/t1/\sqrt{t} — the Cottrell equation, the basis of chronoamperometry and of many electrochemical sensors.

∂c∂t=D ∂2c∂x2i(t)=nFAc∗Dπt\frac{\partial c}{\partial t} = D\,\frac{\partial^2 c}{\partial x^2}\qquad i(t) = \frac{nFAc^{*}\sqrt{D}}{\sqrt{\pi t}}
Fick’s second law and the Cottrell equation (planar electrode, semi-infinite diffusion, zero surface concentration).
DD
diffusion coefficient, cm²/s
c∗c^{*}
bulk concentration, mol/cm³
AA
electrode area, cm²
n,Fn, F
electrons transferred and the Faraday constant
[Fe(CN)₆]⁴⁻ → [Fe(CN)₆]³⁻ + e⁻ · finite-difference diffusion

A potential step: the diffusion layer and the Cottrell current

δ = √(πDt) 020406080100120140Distance from the electrode x / µm00.20.40.60.81c / c*
  • [Fe(CN)₆]⁴⁻ (consumed)
  • [Fe(CN)₆]³⁻ (produced)
00.511.52t / s0100200300400500i / µA
  • Simulated current
  • Cottrell equation × θ/(1 + θ)
Current now
72.1 µA
Diffusion-layer thickness
33 µm
Surface ratio c(O)/c(R) = θ
1.18 × 10⁵
Fick’s second law is solved by explicit finite differences (λ = DΔt/Δx² = 0.45) with a Nernstian surface, c(O)/c(R) = exp[nF(E − E°′)/RT]; both ions have D = 7 × 10⁻⁶ cm²/s (literature 6–8 × 10⁻⁶), the electrode is a 3.0 mm disc (0.0707 cm²), excess supporting electrolyte removes migration and the solution is still. The result agrees with the Cottrell equation within 1 % for t > 0.05 s; the first few time steps are limited by the grid. Double-layer charging is not included.
Drag the time slider or press Play: [Fe(CN)₆]⁴⁻ is depleted near the electrode while [Fe(CN)₆]³⁻ builds up in the same zone, and the dashed line marks √(πDt). Switch to the i–t^(−1/2) view and the current becomes a straight line through the origin. Then lower the step to near E°′: the surface concentration no longer reaches zero, and the current is only θ/(1 + θ) of the limit.

Cyclic voltammetry: there and back

Cyclic voltammetry sweeps the potential linearly at a rate v to a switching potential and back. Starting well below E°′ and sweeping positive, R at the surface begins to oxidise and the current rises; past E°′ the surface is nearly depleted, the current becomes diffusion-limited and falls as the depleted layer thickens — hence a peak. On the return sweep the O piled up near the electrode is reduced again, giving a peak of opposite sign.

For a reversible (Nernstian) couple with fast electron transfer:

  • the mean of the two peak potentials ≈ the formal potential E∘′E^{\circ\prime};
  • the peak separation ΔEp=Epa−Epc≈59/n\Delta E_\mathrm{p} = E_\mathrm{pa} - E_\mathrm{pc} \approx 59/n mV at 25 °C (57–60 mV depending on the switching potential) and does not change with v;
  • the peak current ipi_\mathrm{p} is proportional to v\sqrt{v} and to concentration, and ipa/ipc≈1i_\mathrm{pa}/i_\mathrm{pc} \approx 1.

When electron transfer is slower (quasi-reversible), the surface cannot keep up with Nernstian equilibrium, extra overpotential is needed, and the peaks move apart — further apart the faster the scan. Nicholson described this with the parameter ψ=k∘/πDnFv/RT\psi = k^\circ/\sqrt{\pi D n F v/RT}.

ip=0.4463 nFAc∗nFvDRT=(2.69×105) n3/2A D1/2c∗v1/2(25 ∘C)i_\mathrm{p} = 0.4463\,nFAc^{*}\sqrt{\frac{nFvD}{RT}} = (2.69\times10^{5})\,n^{3/2}A\,D^{1/2}c^{*}v^{1/2}\quad(25\ ^\circ\text{C})
The Randles–Ševčík equation (reversible system). In the second form, i is in A, A in cm², D in cm²/s, c* in mol/cm³ and v in V/s.
ipi_\mathrm{p}
peak current
vv
scan rate, V/s
0.44630.4463
dimensionless peak-current function of a reversible sweep
5 mM [Fe(CN)₆]⁴⁻ at a 3 mm glassy-carbon disc · finite-difference diffusion

Cyclic voltammetry of a reversible couple

Electron-transfer rate constant k°
Electrons n
E°′ −300−200−1000100200300E − E°′ / mV−50050i / µA (anodic positive)
E_pa · E_pc
+29.0 · −29.5 mV
Peak separation ΔE_p
58.6 mV
i_pa (simulated)
79.4 µA
i_p (Randles–Ševčík)
79.4 µA
Concentrations near the electrode at this moment
050100150200250x / µm00.20.40.60.81c / c*
  • [Fe(CN)₆]⁴⁻
  • [Fe(CN)₆]³⁻
Peak current against √v: the Randles–Ševčík plot
0123√v / (V/s)^½0200400600800i_pa / µA
  • Simulated i_pa
  • Randles–Ševčík equation (reversible)
Explicit finite differences solve planar semi-infinite diffusion of O and R (both D = 7 × 10⁻⁶ cm²/s, λ = 0.45, 1 mV per step) with a Nernstian or Butler–Volmer (α = 0.5) surface. The kernel reproduces the Randles–Ševčík constant 0.4463 (within 0.1 %), ΔE_p ≈ 58 mV for a reversible wave (switching 350 mV past E°′) and Nicholson’s ΔE_p–ψ relation. Double-layer capacitance is 20 µF/cm² (typical). Solution resistance (iR drop), convection and coupled chemistry are not included.
Drag the scan-position slider and watch the concentration profile as the current rises, peaks and falls. Then set k° to 0.01 cm/s and 0.001 cm/s and scan faster: the peak separation grows from 58 mV to over a hundred. Finally tick double-layer charging and go to 10 V/s to see the background current prop the voltammogram open.

Worked example

Predicting the size of a CV peak

A 3.0 mm glassy-carbon disc in 5.0 mM [Fe(CN)X6]X4−\ce{[Fe(CN)6]^4-} (1 M KCl, D=7.0×10−6D = 7.0\times10^{-6} cm²/s) is scanned at 0.100 V/s. Estimate the anodic peak current. What happens at 0.400 V/s?

Concept check

A reversible couple gives Epa=+0.262E_\mathrm{pa} = +0.262 V and Epc=+0.203E_\mathrm{pc} = +0.203 V (vs. saturated Ag/AgCl), and the separation does not change with scan rate. Which conclusion is right?

Try the calculation

With the same electrode and solution (A = 0.0707 cm², c* = 5.0 mM, D = 7.0 × 10⁻⁶ cm²/s), what is the Cottrell current 1.00 s after a step to the limiting region, in microamperes?

µA

Key takeaways

  • In a three-electrode cell the potentiostat controls the working electrode against the reference while current returns through the counter electrode.
  • After a potential step the diffusion layer thickens as πDt\sqrt{\pi Dt} and the current decays as 1/t1/\sqrt{t} (Cottrell).
  • Reversible CV: ΔEp≈59/n\Delta E_\mathrm{p} \approx 59/n mV, E∘′≈(Epa+Epc)/2E^{\circ\prime} \approx (E_\mathrm{pa} + E_\mathrm{pc})/2, and ip∝vi_\mathrm{p} \propto \sqrt{v} (Randles–Ševčík).
  • Slower electron transfer makes the separation grow with scan rate; charging current ∝ v limits the sensitivity of CV.
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Data and references

  1. A. J. Bard, L. R. Faulkner, Electrochemical Methods: Fundamentals and Applications, 2nd ed. (Wiley, 2001), Ch. 5 (potential step), Ch. 6 (potential sweep) and Appendix B (digital simulation).
  2. R. S. Nicholson, I. Shain, “Theory of stationary electrode polarography”, Anal. Chem. 36, 706–723 (1964); R. S. Nicholson, Anal. Chem. 37, 1351–1355 (1965).
  3. D. Britz, J. Strutwolf, Digital Simulation in Electrochemistry, 4th ed. (Springer, 2016).
  4. N. Elgrishi et al., “A practical beginner’s guide to cyclic voltammetry”, J. Chem. Educ. 95, 197–206 (2018).
  5. D. C. Harris, Quantitative Chemical Analysis, 9th ed. (2016), Ch. 17 (electroanalytical techniques).