Lesson 5 · 25 min
Real gases
At high pressure and low temperature, molecular attraction and molecular size can no longer be ignored. The compressibility factor measures how far a gas is from ideal; the van der Waals equation explains why and predicts the critical point.
In this lesson
- Measure deviations from ideality with the compressibility factor
- Attribute to attraction and to molecular volume
- Interpret and in the van der Waals equation and use it to predict the critical point
- Judge when the ideal-gas approximation is good enough
A 40 L carbon dioxide cylinder is usually filled with about 25 kg of . At 20 °C the pressure inside is only about 57 bar — most of the contents are liquid, with saturated vapour above. By the ideal-gas equation a 40 L cylinder at 57 bar would hold only about 4 kg, and even at the cylinder’s rated 150 bar only about 11 kg. The ideal-gas equation fails completely here: it assumes that molecules have no volume and do not attract one another, and it is exactly the attraction between molecules that lets be squeezed into a liquid at room temperature.
Predict first
In the molecular-dynamics box, switch on attraction and lower the temperature. What happens to the measured ?
Pick an answer and lock it in before you look. A wrong guess teaches more than no guess.
The compressibility factor
- molar volume
- compressibility factor; exactly 1 for an ideal gas
The van der Waals equation
In 1873 van der Waals made two corrections to the ideal gas law:
- molecules occupy space, so the volume available for motion is reduced by (the “excluded volume” per mole);
- molecules attract one another, lowering the pressure by an amount proportional to the density squared, .
measures the strength of attraction and the size of the molecules; both are fitted to experiment.
- attraction parameter, bar L²/mol² ( 0.035, 3.64)
- excluded volume, L/mol ( 0.024, 0.043)
Worked example
The critical point from van der Waals
From bar L²/mol² and L/mol, find the critical temperature and pressure of and compare with measurement (304.1 K, 73.8 bar).
Concept check
Under which conditions does nitrogen behave most nearly ideally?
Try the calculation
With the van der Waals equation (, ), find the pressure (bar) of 1.00 mol in 0.500 L at 300 K.
Key takeaways
- The compressibility factor measures non-ideality: attraction dominates, molecular volume dominates.
- The van der Waals equation corrects the ideal gas law with (attraction) and (excluded volume) and predicts a critical point.
- Gases are most ideal at high temperature and low pressure; deviations grow at low temperature and high pressure, up to liquefaction.
Data and references
- W. M. Haynes (ed.), CRC Handbook of Chemistry and Physics, 97th ed. (2016), “Van der Waals constants for gases” and “Critical constants”.
- NIST Chemistry WebBook, SRD 69: carbon dioxide critical point (304.13 K, 7.377 MPa).
- P. Atkins, J. de Paula, J. Keeler, Atkins’ Physical Chemistry, 11th ed. (2018), Topic 1C (real gases).