Lesson 11 · 35 min
Metal carbonyls and the 18-electron rule
Why does a neutral nickel atom hold exactly four neutral CO molecules? Count valence electrons, see how σ donation and π back-donation leave a fingerprint in the infrared, and tell isomers apart by counting bands.
In this lesson
- Count the valence electrons of an organometallic compound by the neutral-ligand method and judge from the 18-electron rule whether it is saturated
- Explain the metal–carbonyl bond by σ donation and π back-donation, and use ν(CO) to compare how electron-rich metals are
- Predict the number of infrared ν(CO) bands of a carbonyl complex from its symmetry, and use it to tell isomers apart
In 1890 Ludwig Mond and his co-workers found that carbon monoxide flowing over finely divided nickel carried the metal away: nickel and carbon monoxide combine into a volatile liquid, , boiling at only 43 °C. Mond saw the use at once: crude nickel reacts with CO at 50–60 °C and leaves as a gas, impurities stay behind, and heating the to 220–250 °C returns pure nickel. The Mond process still refines nickel today. But nickel is a neutral atom and CO a neutral molecule — what holds them together, and why exactly four?
Predict first
Iron (group 8) also forms a stable binary carbonyl, . If the metal’s valence electrons plus 2 from each CO make exactly 18, what is x?
Pick an answer and lock it in before you look. A wrong guess teaches more than no guess.
The 18-electron rule
The valence shell of a main-group element is one s and three p orbitals, at most 8 electrons — the octet rule. A transition metal adds five d orbitals: nine valence orbitals, at most 18 electrons. Most stable organometallic compounds fill exactly these 18: the 18-electron rule.
The easiest way to count is the neutral-ligand method: take the metal as a neutral atom giving its group number of valence electrons; give each ligand the electrons it offers as a neutral fragment (2 each for CO and phosphines; 1 each for H, Cl and CH₃; 5 for η⁵-cyclopentadienyl; 6 for η⁶-benzene); add 1 for every metal–metal bond; and subtract the overall charge of the complex.
- valence electrons around the metal
- group number of the metal
- electrons from each ligand as a neutral fragment
- number of metal–metal bonds
- charge on the complex
Worked example
Ferrocene and dimanganese decacarbonyl
Count the valence electrons around each metal in ferrocene, , and in .
σ donation and π back-donation
CO donates the lone pair on its carbon into an empty metal orbital (σ donation); at the same time the metal pushes electrons from its filled d orbitals back into the empty π* orbitals of CO (π back-donation). The two flows reinforce each other and make the metal–carbon bond strong — back-bonding. The price is a weaker C–O bond: π* is antibonding, and the more electrons it receives, the lower the C–O stretching frequency ν(CO).
So ν(CO) is a fingerprint of how electron-rich the metal is. Free CO absorbs at 2143 cm⁻¹ (the band origin of the rotation–vibration band in the spectroscopy unit); across the isoelectronic hexacarbonyls, the more negative the complex, the stronger the back-donation and the lower ν(CO).
Try the calculation
absorbs at ν(CO) = 2000 cm⁻¹ and free CO at 2143 cm⁻¹. Treating C–O as the same oscillator (k ∝ ν̃²), what fraction of free CO’s force constant does the C–O bond keep in the complex?
Ligands change the metal’s electron density as well. Tolman put a range of phosphines L into and measured ν(CO): the strongly donating makes the metal electron-rich and ν(CO) falls to 2056.1 cm⁻¹, while , itself a π acceptor, competes with CO for the metal’s electrons and ν(CO) rises to 2110.8 cm⁻¹. This “Tolman electronic parameter” is still a yardstick for choosing ligands in catalysis.
Counting bands to find a structure
Each C≡O stretch can be treated as one oscillator. Just as for molecular vibrations, the character of an operation is the number of C≡O groups it leaves in place, and reducing it tells how many infrared ν(CO) bands to expect. has six carbonyls yet a single infrared ν(CO) band; has two (2022 and 2000 cm⁻¹). Substitution lowers the symmetry and adds bands, and cis and trans, fac and mer isomers give different counts — which is how chemists often tell which isomer they have just made.
| Complex | Point group | Infrared | Raman |
|---|---|---|---|
| 1 | 2 | ||
| 3 | 4 | ||
| 4 | 4 | ||
| 1 | 2 | ||
| 2 | 2 | ||
| 3 | 3 | ||
| 1 | 2 | ||
| 2 | 3 |
Concept check
A freshly made sample of shows 3 ν(CO) bands in the infrared. Is it fac or mer?
Key takeaways
- Valence electrons N = group number + ligand electrons + M–M bonds − charge; 18 fill the nine valence orbitals, and most stable organometallics have 18.
- 17-electron species tend to gain an electron or form M–M bonds, 19-electron species to lose one; square-planar d⁸ complexes often have 16.
- σ donation and π back-donation strengthen M–C and weaken C–O; the more electron-rich the metal, the lower ν(CO) (free CO 2143, Cr(CO)₆ 2000 cm⁻¹).
- The number of ν(CO) bands follows from symmetry: 1 for M(CO)₆, 2 for fac-M(CO)₃L₃, 3 for mer, 4 for cis-M(CO)₄L₂ and 1 for trans.
Data and references
- L. Mond, C. Langer and F. Quincke, “Action of carbon monoxide on nickel”, J. Chem. Soc., Trans. 57, 749–753 (1890).
- C. A. Tolman, “Steric effects of phosphorus ligands in organometallic chemistry and homogeneous catalysis”, Chem. Rev. 77, 313–348 (1977).
- C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018, chapter 24 (organometallic compounds of the d-block).
- F. A. Cotton, Chemical Applications of Group Theory, 3rd ed., Wiley, 1990, chapter 10 (vibrations; carbonyl stretching bands).
- Wikipedia, “Metal carbonyl”, table of ν(CO) for the isoelectronic hexacarbonyls (accessed 2026-09-29; sources there include J. E. Ellis and K.-M. Chi, J. Am. Chem. Soc. 112, 6022 (1990), and M. Finze et al., Inorg. Chem. 44, 4206 (2005)).